Question

The radius of a circle is 13 cm and the length of one of it’s chord is 10 cm.

Find the distance of the chord from the centre.​

Answer 1

Step-by-step explanation:

Let AB be a chord of a circle with centre O and radius 13 cm such that AB = 10 cm.

From O, draw OL ⊥ AB. Join OA.

Since, the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = LB = ½ AB = 5 cm

Now, in right triangle OLA, we have

OA2 = OL2 + AL2

⇒ 132 = OL2 = 52

⇒ 132 – 52 = OL2

⇒ OL2 = 144

⇒ OL = 12 cm.

Hence, the distance of the chord from the centre is 12 cm.

Answer 2

Answer:

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