The radius of a circle is 13 cm and the length of one of its chords is 10 cm. The distance of the chord from the center is -
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Answer:
let AB be the chord of the circle with centre O and radius 13cm such that AB=10 cm
from O,draw the OL parallel to AB.join A
since,the perpendicular form of a centre of circle to chord bisects the chord
therefore,AB=LB=½AB=5cm
now in right angle triangle, OLA we have
OA²=OL²+AL²
13²=OL²+5²
13²-5²=OL²
OL²=144cm
OL= 12cm
Hence the distance of the chord from the centre is 12cm
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Since, the perpendicular from the centre of a circle to a chord bisects the chord. ⇒ OL = 12 cm. Hence, the distance of the chord from the centre is 12 cm.
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