Question

the radius of a circle is 13 cm and the length of one of its chords is 24 cm. find the distance of the chord from the centre ?

Answer 1

Dist. of half chord=24/2=12cm(since line drawn perpendicular to chords for the centre bisect the chord)

A right angled triangle is made;

By using Pythagoras Theorem:

(13)^2=(12)^2+x^2 (let dist between chord and centre=x)

169=144+x^2

x^2=169-144

x^2=25

x= √25=5cm

Therefore, the dist. between the chord and centre is 5cm.

Answer 2

5cm (answer)

We are given the radius of the circle which is given as 13cm.

The length of the chord is given 24cm.

As it forms a right angle triangle.

So, we will use the Pythagoras formula here.

That is P²+B²=H²(P=perpendicular, B=Base, H=Hypotenuse)

so, here the hypotenuse is the radius and the chord is the base .

so, applying Pythagoras formula=

⇒P²+12²=13²

⇒P²=25

⇒P=5cm(answer)