Question

THE RADIUS OF A CIRCLE IS 13 CM
ONE OF ITS CORD IS 24 CM
FUND THE DISTANCE OF YHE CORD FROM CENTRE​

Answer 1

GIVEN:

A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm

TO FIND :

• The perpendicular distance of the chord from O. Let it be called OM.
• OM is perpendicular to the chord AB.
• Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm
• In right triangle AMO , Using Pythagoras’s Theorem,

AO² = AM² + OM²

=> 13² = 12² + OM²

=> 169 = 144 + OM²

=> OM² = 169 - 144 = 25

=> OM = √25 = 5 cm.

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Answer 2

Answer:

hi

GIVEN:

A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm

TO FIND :

The perpendicular distance of the chord from O. Let it be called OM.

OM is perpendicular to the chord AB.

Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm

In right triangle AMO , Using Pythagoras’s Theorem,

AO² = AM² + OM²

=> 13² = 12² + OM²

=> 169 = 144 + OM²

=> OM² = 169 - 144 = 25

=> OM = √25 = 5 cm.

Step-by-step explanation:

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