The radius of a circle is 13cm. and the length of one of its chords is 24 cm. find the distance of the chord from the centre
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Answer:
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Step-by-step explanation:
The radius of a circle is 13 cm and length of one chord is 24 cm. What is the distance of chord from center?
5 Answers

Edwin Koh
Answered January 31, 2018 · Author has 990 answers and 838.2K answer views
GIVEN: A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm
TO FIND : The perpendicular distance of the chord from O. Let it be called OM.
OM is perpendicular to the chord AB.
Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm
In right triangle AMO , Using Pythagoras’s Theorem,
AO² = AM² + OM²
=> 13² = 12² + OM²
=> 169 = 144 + OM²
=> OM² = 169 - 144 = 25
=> OM = √25 = 5 cm.
Answer:
5cm
Step-by-step explanation:
As the chord is of 24cm..if we draw a perpendicular to the chord..the chord will be divided into two parts of 12cm each forming a right angled triangle of hypotenuse=radius=13cm
Therefore..by Pythagoras theorem
13^2=12^2+x^2
169=144+x^2
x^2=25
Therefore x=5cm
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