Question

The radius of a circle is 13cm and the length of one of

its chord is 24cm. find the distance of chord from the

centre.​

Answer 1

Answer:

Step-by-step explanation:

GIVEN: A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm

TO FIND : The perpendicular distance of the chord from O. Let it be called OM.

OM is perpendicular to the chord AB.

Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm

In right triangle AMO , Using Pythagoras’s Theorem,

AO² = AM² + OM²

=> 13² = 12² + OM²

=> 169 = 144 + OM²

=> OM² = 169 - 144 = 25

=> OM = √25 = 5 cm.

hope it helps

thankyou......

Answer 2

Answer:

5 cm

Step-by-step explanation:

Use the property that perpendicular from the centre to a chord bisects the chord.

Now apply Pythagoras Theorem

(13)^2 - (12)^2 = 169 - 144 = 25

Square root of 25 is 5

hence the answer is 5 cm.

Draw the figure yourself too.