Question

The radius of a circle is 16cm and the length of one of its chord is 24cm then the distance of the chord from the centre is :- (a) 10.24cm (b) 10.26cm (c) 10.58cm (c) 10.22cm - ​

Answer 1

Answer:

GIVEN: A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm

TO FIND : The perpendicular distance of the chord from O. Let it be called OM.

OM is perpendicular to the chord AB.

Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm

In right triangle AMO , Using Pythagoras’s Theorem,

AO² = AM² + OM²

=> 13² = 12² + OM²

=> 169 = 144 + OM²

=> OM² = 169 - 144 = 25

=> OM = √25 = 5 cm.

Answer 2

GIVEN:-

A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm

TO FIND :

The perpendicular distance of the chord from O. Let it be called OM.

OM is perpendicular to the chord AB.

Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm

In right triangle AMO , Using Pythagoras’s Theorem,

AO² = AM² + OM²

=> 13² = 12² + OM²

=> 169 = 144 + OM²

=> OM² = 169 - 144 = 25

=> OM = √25 = 5 cm.

HOPE THIS HELPS ⭐⭐

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