The radius of a circle is 17 cm. A chord of length 30 cm is drawn.
Find the distance of the chord from the centre.
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Step-by-step explanation:
17 multiply by 30 ooooooooooooooooook pl mark me in brain list
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Answer:
by theorem we know that a line joining from centre to the chord is always perpendicular bisector of chord to the chord
hence OL is perpendicular to chord AB
now in ∆OLB
(OL)^2=(OB)^2-(LB)^2
(OL)^2= 17^2-15^2
OL=√289-225
OL=√64
OL= 8 cm
hence OL = 8 cm ( distance from the centre)
hope helped
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