Question

The radius of a circle is 17 cm. A chord of length 30 cm is drawn. Find the distance of the chord from the centre.

plz answer step wise urgent

Answer 1

Hello Mate!

Given : Radius of circle is 17 cm and chord length = 30 cm.

Point that matter : Distance from chord to center. Thid means the distance from mid ooint of chord to the center and we know by theorum that line from centre that bisects AB is perpendicular bisector.

To find : OL.

Solution : AL = ½ AB

AL = ½ × 30 cm

AL = 15 cm

In right ∆BOL,

OB² = OL² + BL²

17² = OL² + 15²

17² - 15² = OL²

√[( 17 + 15 )( 17 - 15 )] = OL

√( 32 × 2 ) = OL

8 cm = OL

Hence radius and chord are at the distance of 8 cm.

"Have great future ahead!"

Answer 2

hey
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•by theorem we know that a line joining from centre to the chord is always perpendicular bisector of chord to the chord

hence OL is perpendicular to chord AB

now in ∆OLB
(OL)^2=(OB)^2-(LB)^2
(OL)^2= 17^2-15^2
OL=√289-225
OL=√64
OL= 8 cm

hence OL = 8 cm ( distance from the centre)

hope helped
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