the radius of a circle is 17 cm a chord of length 30cm is drawn find the distance of the chord from the centre
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Step-by-step explanation:
Given the radius of a circle is 17 cm a chord of length 30 cm is drawn find the distance of the chord from the centre
- Given radius of a circle is 17 cm and length of the chord is 30 cm
- We need to find the distance from midpoint of chord to the centre. So perpendicular bisector is the line from centre that bisects MN
- So let OP be the perpendicular to chord MN, P is the midpoint of MN
- So MP = ½ of MN
- Or MP = ½ x 30
- = 15 cm
- From the right angle triangle NOP we have
- So ON^2 = OP^2 + PN^2
- 17^2 = OP^2 + 15^2
- OP^2 = 17^2 – 15^2
- Or OP^2 = (17 + 15) (17 – 15)
- Or OP^2 = 32 x 2
- Or OP^2 = 64
- Or OP = 8 cm
- Therefore the distance of the chord from the centre is 8 cm
Reference link will be
https://brainly.in/question/7314658
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1
Answer:
OP=8cm
hope it helps you
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