Question

the radius of a circle is 17 cm a chord of length 30cm is drawn find the distance of the chord from the centre​

Answer 1

Step-by-step explanation:

Given the radius of a circle is 17 cm a chord of length 30 cm is drawn find the distance of the chord from the centre

• Given radius of a circle is 17 cm and length of the chord is 30 cm
• We need to find the distance from midpoint of chord to the centre. So perpendicular bisector is the line from centre that bisects MN
• So let OP be the perpendicular to chord MN, P is the midpoint of MN
• So MP = ½ of MN
• Or MP = ½ x 30
•             = 15 cm
• From the right angle triangle NOP we have
•       So ON^2 = OP^2 + PN^2
•              17^2 = OP^2 + 15^2
•              OP^2 = 17^2 – 15^2
•             Or OP^2 = (17 + 15) (17 – 15)
•        Or OP^2 = 32 x 2
•        Or OP^2 = 64
•        Or OP = 8 cm
• Therefore the distance of the chord from the centre is 8 cm

Reference link will be

https://brainly.in/question/7314658

Answer 2

Answer:

OP=8cm

hope it helps you