Question

the radius of a circle is 20 metre and second circle is 48 M find the radius of the circle whose area is equal to sum of areas of two circles

Answer 1

area of 1st circle=22/7×20×20=1257.14m^2
area of 2nd circle =22/7 48×48= 7241.14m^
area of 3rd circle = 1257.14+7241.14
22/7×r^2=8498.28
r= 52m (approx)

Answer 2

Let R be the radius of the third Circle

Here radius of two circles given is 20 m and 48 m

Given that

Sum of Area of given two circles = Area of another (third) circle

We know that area of circle = π(radius)²

∴ π (20)² + π(48)² =πR²

Taking π common from LHS

π ( 20² + 48²) = πR²

Dividing both sides by π

20² + 48² = R²

R² = 400 + 2304

R² = 2704

R = √2704

R = 52

∴ Radius of third circle is 52 m