Question

The Radius Of A Circle Is 25cm. PQ And RS Are Two Parallel Chords 17cm Apart. PQ = 48cm, Then RS Is Approx. Equal To

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Answer 1

Answer:

RS=45.82cm

Step-by-step explanation:

PQ=48 cm

therefore, PM=MQ=48/2cm=24cm

In right angled triangle MQO, By pythagoras theorem,

OQ^2=MO^2+MQ^2

25^2=MO^2+24^2

MO^2=625-576

MO^2=49

MO=7cm

but we know that MN=17

where MN=MO+ON

therefore, 17=7+ON

ON=17-7

ON=10cm

In right angled triangle ONS, By pythagoras Theorem,

OS^2=ON^2+NS^2

25^2=10^2+NS^2

NS^2=625-100

NS^2=525

NS=22.91cm

but we know that RS=2×NS

therefore, RS=2×22.91

Rs=45.82cm