the radius of a circle is 30 cm. find the length of an arc ,if the length of the chord of the arc is 30 cm
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LET TAKE THAT CHORD AS AB = 30 CM IN O CENTRE OF CIRCLE AND JION OA AND OB SO OA = OB = 30 CM
SO ∆OAB IS EQUILATERAL TRIANGLE WE KNOW THAT IN EQUILATERAL TRIANGLE EACH ANGLE EQUALS TO 60 °
SO O = 60 ° = π/3 RADIAN
WE KNOW THAT IF 'O' ANGLE SUBTENDED AT CENTRE BY 'L' LENGTH OF ARC IN 'R' RADIUS OF CIRCLE THEN
O = L/R
O × R = L
π/3 × 30 = L
10π = L
SO THE LENGTH OF THE ARC OF CHORD IS = L = 10π CM
SO ∆OAB IS EQUILATERAL TRIANGLE WE KNOW THAT IN EQUILATERAL TRIANGLE EACH ANGLE EQUALS TO 60 °
SO O = 60 ° = π/3 RADIAN
WE KNOW THAT IF 'O' ANGLE SUBTENDED AT CENTRE BY 'L' LENGTH OF ARC IN 'R' RADIUS OF CIRCLE THEN
O = L/R
O × R = L
π/3 × 30 = L
10π = L
SO THE LENGTH OF THE ARC OF CHORD IS = L = 10π CM
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Answer:
Radius = 30 cm
Angle =60° (1° = π/180)
60° = 60*π/180 = π/3
l = rΦ
l = 30*π/3
l= 10π
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