The radius of a circle is 41 cm the length of one
of its chord is 80cm find the distance of the chord
from the centre.
Answers
Answered by
4
Answer:
hope it helps! please mark as brainliest
Attachments:
Answered by
14
Answer:
Radius of circle (OA) = 41cm
Chord (AB) = 80cm
Draw OC⊥AB
We know that
The perpendicular from centre to chord bisects the chord
∴AC=BC=802=40cm
Now in ΔOCA, by Pythagoras theorem
AC2 + OC2 = OA2
=>402 + OC2 = 412
=>1600 + OC2 = 1681
=>OC2 = 81
=> OC2 = 81
=>OC = 81−−√
=>OC = 9cm
☆ I hope its help you ☆
Similar questions