Question

the radius of a circle is 5cm perpendicular is dropped from the centre O to chord AB meeting it at E. If AB=8cm, find the distant from centre to the chord.​

Answer 1

Answer:

Construct AO

OE=height

AE=1/2 of AB= 4cm

AO=radius =hypotenuse=5 cm

By pythagoras theorem

the distance of the chord from the centre is 3 cm.

Answer 2

Answer:

OE=3cm

Step-by-step explanation:

Given:AB=8cm

Thus AE=EB=4cm

Radius OB=5cm

Let us take OE as x

By Pythagoras theorem,

h^2=p^2+b^2

(5)^2= (x)^2 + (4)^2

25=x^2 + 16

25-16= x^2

9= x^2

x=3