the radius of a circle is 5cm . the distance of a chord from the centre is 4cm. find the length of the chord.
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Answer:
In the given circle, radius OA = 5 cm: distance of the chord AB from the centre is 4 cm.
So, seg AM = seg MB (Perpendicular drawn from the centre to a chord bisects the chord)
By using Pythagoras theorem, in right triangle AOM,
AM2 + OM2 = OA2
⇒ AM2 + 42 = 52
⇒ AM2 +16 = 25
⇒ AM2 = 25 – 16
⇒ AM2 = 9
⇒ AM = 3 cm
But seg AM = seg MB = 3 cm
∴ Seg AB = seg AM + seg MB = 3 cm + 3 cm = 6 cm
Therefore, the length of the chord is 6 cm.
Answered by
1
Answer: In the given circle, radius OA = 5 cm: distance of the chord AB from the centre is 4 cm. Therefore, the length of the chord is 6 cm.
Step-by-step explanation:
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