Question

The radius of a circle is 6 cm and the length of one of its chords is 6 cm. Find the distance of the chord from
the centre.​

Answer 1

Answer:

See the given attachment

Answer 2

$\huge \bold {\underline{ \: question}}$

The radius of a circle is 6 cm and the length of one of its chords is 6 cm. Find the distance of the chord from

the centre.

Given:

• The radius of circle is 6 cm.
• The length of 1 of its chord is 6cm

To Find:

• The distance of chord from the centre

Solution:

O is a centre.

We know that ,

Perpendicular from centre of chords bisects it.

So,

AP = BP

and in , △ OPA

r² = (OA)² = (OP)² + (AP)²

$(6)^{2} =( OP) ^{2} + (\frac{AB}{2} {)}^{2} \\ \\ 36 \: = (OP)^{2} + {3}^{2} \\ \\ (OP) = 36 - 9 \\ \\ OP = \sqrt{27} \\ \\ OP = 3 \sqrt{3}$

$\bold{distance \: of \: the \: chord \: from \: the \: centre \: is \: 3 \sqrt{3}}$