Question

The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is
A. √5 cm
B. 2 √5 cm
C. 2 √7 cm
D. √7 cm

Answer 1

Answer:

\[2\sqrt{5}\] cm

We will represent the given data in the figure.

We know that perpendicular drawn from the centre to the chord divides the chord into two equal parts.

So , AM = MB = \[\frac{AB}{2} = \frac{8}{2}\] = 4 cm.

Using Pythagoras theorem in the ΔAMO,

`OM^2 = AO^2 - AM^2`

`= 6^2 - 4^2`

= 36-16

`= sqrt(20)`

= `2sqrt(5)` cm

Answer 2

Answer:

We know that perpendicular drawn from the centre to the chord divides the chord into two equal parts. So , AM = MB = A B 2 = 8 2 = 4 cm