the radius of a circle is 6 CM the perpendicular distance from the centre of the circle to the cord which is 8 cm in length is
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Answer:
2√5 cm
Step-by-step explanation:
Use the image given below for reference.
Radius = 6 cm = OA
OP is perpendicular to AB
We know that perpendicular from centre bisects a chord.
Thus, AP = BP = 8/2 => 4 cm.
Applying Pythagoras' theorem,
OP² = OA² – AP²
=> OP² = 6² - 4²
=> OP² = 36 - 16 --> 20
∴ OP² = √20 => 2√5 cm
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