Question

The radius of a circle is 6cm. Find the distance of the chord from the center if the length of the chord is 6cm

Answer 1

here, radius i.e AP = 6cm
Length of chord i.e AB = 6CM
TO FIND - PM = ?

AM = 1/2 × AB { PERPENDICULAR DRAWN FROM THE CENTRE TO THE CHORD BISECTS THE CHORD}
AM = 1/2 × 6
AM = 3CM

IN RIGHT ANGLE TRIANGLE PMA, BY PYTHAGORAS THEOREM

(hypotenuse)^2 = ( one side)^2 + ( other side )^2
(PA)^2 = (PM)^2 + (AM)^2
(6)^2 = (PM)^2 + (3)^2
36 = (PM)^2 + 9
36 - 9 = (PM)^2
27 = (PM)^2
$\sqrt{27} = pm$