Question

the radius of a circle is 8 cm and the lenght of one of the chord is 12cm. Find the distance of chord from the centre

Answer 1

I hope it will help you

Answer 2

By Pythagoras Theorem,

$Radius^{2} = (half of chord)^{2} + distance^{2}$

putting the values,

$8^{2} = (12/2) ^{2} + distance^{2}$


64 = 36 + $distance ^{2}$



64 - 36 = $distance^{2}$


28 =$distance^{2}$



$\sqrt{28} = distance$

$2 \sqrt{7} = distance$

Now,

 the distance is $2 \sqrt{7}$ cm   



i hope this will help you


-by ABHAY