the radius of a circle is 8cm and the length of one of its chords is 12cm.find the distance of the chord from the centre
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Draw a perpendicular on the given chord from the center of the circle
we know it divides the chord in to equal parts
Join the centre of circle and end point of the chord
you will get right angled triangle
let the distance be x
using Pythagorean theorem
8²=6²+x²
64=36+x²
x²=28
x=√28
x=2√7
we know it divides the chord in to equal parts
Join the centre of circle and end point of the chord
you will get right angled triangle
let the distance be x
using Pythagorean theorem
8²=6²+x²
64=36+x²
x²=28
x=√28
x=2√7
sacheev:
thx vvv much
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