The radius of a circle is 9 cm and length of one of its chords is 14 cm. find the distance of the chord from the centre.
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♦ Elementary Geometry ♦
→ Draw the perpendicular bisector of the chord
→ Recall : Perpendicular to a chord from the center bisects it
=> You get a Right Angled Triangle with right angle lying at the point of bisection of the chord
• Applying Pythagoras :
--> Radius² = ( 1/2 chord )² + ( distance of chord from center )²
=> [ Distance of Chord from Center ]² = ( 9² ) - ( 7² ) = 32
=> [ Distance of Chord from Center ] = √32 = 4√2 cm
_____________________________________________________________
♦ Elementary Geometry ♦
→ Draw the perpendicular bisector of the chord
→ Recall : Perpendicular to a chord from the center bisects it
=> You get a Right Angled Triangle with right angle lying at the point of bisection of the chord
• Applying Pythagoras :
--> Radius² = ( 1/2 chord )² + ( distance of chord from center )²
=> [ Distance of Chord from Center ]² = ( 9² ) - ( 7² ) = 32
=> [ Distance of Chord from Center ] = √32 = 4√2 cm
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