The radius of a circle is decreased by 2m, then the ratio of the area of the original circle to the reduced circle becomes 3 : 1. Find its radius.
(A) (√3+1) m
(C) (13-1) m
(B) (√3+3) m
(D) 2√3 m
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Given info : The radius of a circle is decreased by 2m, then the ratio of the area of the original circle to the reduced circle becomes 3 : 1.
To find : the radius of the circle is ...
solution : let the radius of the circle is r.
initial area of circle , A = πr²
now radius is decreased by 2m, i.e., (r - 2)
so, area, A' = π(r - 2)²
a/c to question, A/A' = 3/1
⇒πr²/π(r - 2)² = 3/1
⇒r/(r - 2) = √3/1
⇒r = √3r - 2√3
⇒(√3 - 1)r = 2√3
⇒r = 2√3/(√3 - 1) = 2√3(√3 + 1)/2 = √3(√3 + 1)
= 3 + √3
Therefore the radius of the circle is 3 + √3.
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