English, asked by keyan887, 10 months ago

The radius of a circle with centre (-2,3) is 5 units .the point (2,5) lies

Answers

Answered by muthyalasravani1729
3

Answer:

lies inside the circle

Explanation:

given center of the circle is (-2,3) and radius 5

the circle equation having center (h,k) is

the circle equation having center (h,k) is(x-h)^2+(y-k)^2=r^2

here (h,k)= (-2,3) and r=5

then the equation of circle with centre (-2,3) and radius 5 is

(x-(-2))^2+(y-3)^2=(5)^2

(x+2)^2+(y-3)^2=25

x^2+4+4x+y^2+9-6y=25

x^2+y^2+4x-6y+13=25

x^2+y^2+4x-6y-12=0

x^2+y^2+4x-6y-12=0 this is equation of circle of given center and radius

concept:

_______________________________________

if point (x1,y1) lies

(i) lies on the circle, if when we substitute the

point in circle equation then the value should

be equal to zero

(ii) lies inside the circle , if when when we

substitute the point in circle equation then the

value should be less than zero

(iii) lies outside the circle, if when when we

substitute the point in circle equation then the

value should be greater than zero

_______________________________________

based on the conditions we have to consider where the point lies

here (x1,y1) is (2,5)

substitute the point in circle equation

= (2)^2+(5)^2+4(2)-6(5)-12

= 4+25+8-30-12

= -5<0

here the value is less than zero

therefore , the given point lies inside the circle

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