the radius of a circle with Centre P is 25 the length of a chord of a circle is 48 centimetre find the distance of a chord from the centre of a circle
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Answer:7
Step-by-step explanation:Let CD be the chord and PD the radius
Cons:Draw OP perpendicular bisector to CD
Then OD = OC =48/2=24. ( we know perpendiculars drawn from the centre to the chord bisects the chord)
In ∆OPD
ANGLE O =90°
Therefore using Pythagoras theorem
OP^2 +OD^2 = PD^2
OP^2= 25^2 -24^2
= 625-576
= 49
OP=√49
OP = 7
Hope this may help you!!
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