The radius of a circular ground is
56 m. A 7 m wide road runs around its boundary inside
the ground. Some region of the road as shown by shaded part in the diagram is to be repaired. Find the cost of repairing at the rate of 40/m2.
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Answer:
₹15,490
Step-by-step explanation:
let, smaller radius=r1 and bigger radius=r2
Area of shaded part=
area of bigger sector - area of smaller sector
= π x r2 x r2 x theta÷360 - π x r1 x r1 x theta÷ 360
= π x theta ÷ 360(r2²-r1²)
=22/7 x 60/360 (3136-2401)
=385m²
So,
cost of repairing=385 x 40= ₹15,400(ans)
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