Question

the radius of a circular park is 18.2 metres a road 2.5 m wide runs around it. find the cost of graveling the road at ₹8 per m square​

Answer 1

Answer:

305.34 m² is the area of path. ₹2445.12 is the cost of graveling.

Step-by-step explanation:

Area of a circle = πr²

Area of Circular Park along with the road = $\frac{22}{7}$ × (18.2 + 2.5)²

⇒ $\frac{22}{7}$ × 20.7²

⇒ $\frac{22}{7}$ × 428.49

⇒ 1346.68 m²

Area of Circular Park along with the road = 1346.68 m²

Area of the Circular Park = $\frac{22}{7}$ × 18.2²

⇒ $\frac{22}{7}$ × 331.24

⇒ 1041.04 m²

Area of the Circular Park = 1041.04 m²

Area of Road = Area of Circular Park along with the road - Area of the Circular Park

Area of Road = 1346.68 m² - 1041.04 m²

Area of Road = 305.64 m²

Cost of Graveling the road = 305.64 m² × ₹8 = ₹2445.12

Therefore, 305.34 m² is the area of path. ₹2445.12 is the cost of graveling.

Answer 2

Answer:

Above answer is correct

Mark above answer as brainliest