Math, asked by anjalikumari21, 26 days ago

the radius of a circular park is 56 m. if a road 3.5 m wide is made around it on the outside , find the cost of constructing the road at the rate of rs 25 per square metre.

please solve it

with process​

Answers

Answered by abhiraj33181
0

Answer:

56 \times 3.5

 \frac{196}{25}  = 7.24

Answered by kshmashukla7a27
0

First the area of the circular park

= Pi r^2

=22/7*56^2

=22/7*3136

=22*448

=9856 metre square

Area of park along with road

Then radius of park along with the road

=56+3.5

=59.5metres

Therefore area of park along with the road

= Pi r^2

=3.14*59.5^2

=3.14*3540.25

=11116.385 metre square

Therefore the area of the road =

Area of park along with the road -area of park

=11116.385-9856

=1260.385 metre square

Cost of construction of road

=area of road *25

=1260.385*25

=Rs. 31509.625

Hope this was helpful

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