The radius of a circular sheet of copper measured at 25°C was 20 cm. The change in area of the sheet when temperature is increased ti thrice the initial temperature is.(Coefficient of linear expansion of copper is 17 x 106/°C
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1
Initial area A=π(35)2=3846.5cm2
Change in area on heating ΔA=14.5cm2
α=1.7×10−5
We know that area expansion coefficient is twice of linear expansion coefficient.
So β=2α=2×1.7×10−5=3.4×10−5
So ΔA=AβΔt
14.5=3846.5×3.4×10−5×ΔT
ΔT=110.8oC
Answered by
2
Initial area A=π(35)2=3846.5cm2
Change in area on heating ΔA=14.5cm2
α=1.7×10−5
We know that area expansion coefficient is twice of linear expansion coefficient.
So β=2α=2×1.7×10−5=3.4×10−5
So ΔA=AβΔt
14.5=3846.5×3.4×10−5×ΔT
ΔT=110.8oC
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