Question

the radius of a circular sheet of metal is 14cm a circular sheet is cut out of it. the radius of the remaining piece is 7cm. what is the area of the cut out piece? ​

Answer 1

The area of the original sheet = (pi)r^2 = (22/7)*196 = 616 sq cm.

The area of the 2 small circles cut out = 2*(pi)r^2 = 2(22/7)*3.5^2 = 77 sq cm.

The area of the remaining sheet = 616–77 = 539 sq cm.

Answer 2

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Here is the solution.

$area \: of \: complete \: sheet \: = 2\pi\: {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = > 616 {cm}^{2} \\ \\ area \: of \: remaining \: sheet \: = \pi {r}^{2} \\ \frac{22}{7} \times 7 \times 7 \\ = > 154 {cm}^{2} \\ \\ area \: of \: the \: cut \: out \: sheet \: = (616 - 154) {cm}^{2} \\ \\ = > 462 {cm}^{2} ans$