Question

the radius of a closed cylinder is 7 cm and its total surface area is 528 cm².find the height of the cylinder

Answer 1

Given,
R=7cm
TSA=528 sq cm

To find, Height(h)
TSA of cylinder= 2$\pi$r(r+h)
528sq cm= 2x22÷7x7(7+h)
528sq cm=2x22(7+h)
264sq cm=22(7+h)
264÷22=7+h
132÷11=7+h
12=7+h
therefore, h=12-7
h=5cm

Answer 2

or,or,or,Radius=7cm
TSA=5or,28 cm²
Let the height be x,we get
TSA=2πr(h+r)
or,528=2*22/7*7(x+7)
or,264=22*(x+7)
or,12=x+7
or,x=12-7
or,x=5 cm
So,
Height=5 cm