The radius of a coin is 1 cm. If four of these coins are placed in a square arrangement on a table so that the rim of each touches that of the other two, find the area of the unoccupied space between them ?
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Side of a square formed=4cm
So, area of square formed=4*4sq.cm
Radius of a coin=1cm
therefore, area of a coin=4×22/7×1×1sq.cm
now, according to question
Area of unoccupied space=4×4-4×22/7
=16-12.57
=3.43
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