Question

the radius of a cricle is 7cm . the angle subtended by an arc of a cricle at centre is 45°. find the area of sector​

Answer 1

Answer:

77/4 cm²  or 19.25 cm²

Step-by-step explanation:

given angle subtended at the centre , D = 45° and r=7cm

=> area of the sector = (D/360)* $\pi r^{2}$

                                   = (45/360) * (22/7) * (7*7) cm²

                                   = (5/40)*22*7

                                   = (1/8)*22*7

                                   = (1/4)*11*7

                                   = 77/4 cm²  or 19.25 cm²

Answer 2

Answer:

area of sector is Theta/ 360×πr^2

so here theta is 45

r is 7 cm

so area of sector is 45/360× 22/7 × 7×7

so ans is 19.25