Question

The radius of a cycle 10 cm and the length of a chord is 12 cm then, calculate distance between the cord and the center of the circle

Answer 1

Answer :-

☞$\bf{\underline\red{8cm}}$

Step by step explanation -

$\bf{\underline\red{Given\: ,}}$

$\bf{\underline\orange{Chord\: of \:the \:circle\: =\: 12\: cm}}$

$\bf{\underline\orange{Half \:the \:chord\: length\: =\: 6\: cm}}$

$\bf{\underline\orange{Radius \:of\: the \:circle\: = \:10\: cm}}$

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• A , C = endpoints of chord
• B = mid point of chord
• O = center of the circle

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OA (radius) = 10cm

AC = 12cm ( AB = 6cm , BC = 6cm )

OB = ?cm

By pythagoras theorem :

➪OB² + AB² = OA²

➪ OB² + (6cm)² = (10cm)²

➪ OB² + 36cm² = 100cm²

➪ OB² = ( 100 - 36 ) cm²

➪ OB² = 64 cm²

➪ OB = 8cm × 8cm

➪ OB = 8cm $\bf{\underline\red{Answer}}$

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