Question

The radius of a cylinder is 7cm, while its volume is 1.54L. What is the height of the cylinder. Take $\pi = 22/7$

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Answer 1

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Given:

• Volume of the cylinder = 1.54L

• Radius of cylinder = 7cm

To Find:

• Height of cylinder

Solution:

We know that,

1L = 1000 $cm^3$

1.54L = 1.54*1000 => 1540 $cm^3$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{7}}\put(9,17.5){\sf{h}}\end{picture}$

Volume of cylinder = $\pi*r^2*h$

1540 = $\dfrac{22}{7}*7^2*h$

1540 = 22*7*h

154*h = 1540

h = 10.

The height of the cylinder is 10cm.

Formula Used:

• Volume of cylinder = $\pi*r^2*h$

Learn More:

• Volume of cylinder = πr²h

• T.S.A of cylinder = 2πrh + 2πr²

• Volume of cone = ⅓ πr²h

• C.S.A of cone = πrl

• T.S.A of cone = πrl + πr²

• Volume of cuboid = l × b × h

• C.S.A of cuboid = 2(l + b)h

• T.S.A of cuboid = 2(lb + bh + lh)

• C.S.A of cube = 4a²

• T.S.A of cube = 6a²

• Volume of cube = a³

• Volume of sphere = (4/3)πr³

• Surface area of sphere = 4πr²

• Volume of hemisphere = ⅔ πr³

• C.S.A of hemisphere = 2πr²

• T.S.A of hemisphere = 3πr²

Answer 2

hello.

the height of the cylinder is 10cm

hope it helps!