the radius of a cylinder is increasing at a rate of 1 metre per hour, and the height of the cylinder is decreasing at a rate of 4 metres per hour, at a certain instant , the radius is 5 metres and the hight is 8 metres. what is the rate of change of the volume of the cylinder at the instant?
Answers
Answered by
0
Answer:
Given
dt
dr
=1 and
dt
dh
=−1
We know that, Volume of a cylinder is given by
V=πr
2
h
⟹
dt
dV
=π2rh
dt
dr
+πr
2
dt
dh
⟹
dt
dV
=πr(2h(1)+r(−1))
=π×5(2×15−5)
=125π
Similar questions