Question

The radius of a cylindrical tank is 14 m. And height 20 m. Is.Find the area of ​​curvature of the cylindrical tank.(ii) Find the total surface area of ​​a cylindrical tank.(iii) Find the volume of a cylindrical tank.​

Answer 1

$\bf \underline{Given} :$ ↴

$\sf \implies Radius \: of \: cylindrical \: tank = 14 \: metre$

$\sf \implies Height \: of \: cylindrical \: tank = 20 \: metre$

$\bf \underline{To \: find} :$ ↴

$\sf \implies Area \: of \: curvature \: of \: cylindrical \: tank.$

$\sf \implies Total \: surface \: area \: of \: cylindrical \: tank.$

$\sf \implies Volume \: of \: cylindrical \: tank.$

$\bf\underline{ \underline{Solution} }$

$\sf (i). \: Area \: of \: curvature = Curved \: Surface \: area = 2 \pi r h$

$\sf \implies Curved \: Surface \: area = 2 \pi r h$

$\sf \implies 2 \times \dfrac{22}{7} \times 14 \times 20$

$\sf \implies 2 \times \dfrac{22}{7} \times 280$

$\sf \implies \dfrac{44}{7} \times 280$

$\sf \implies 44 \times 40$

$\sf \implies 1760 \: m^{2}$

$\boxed{\pink{ \sf Hence, area \: of \: curvature = 1760 \: m^{2}}}$

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$\sf (ii).\: Total \: surface \: area \: of \: cylinder = 2 \pi r(h + r)$

$\sf \implies 2 \times \dfrac{22}{7} \times\: 14 \times (20 + 14)$

$\sf \implies 2 \times 22 \times\: 2 \times (20 + 14)$

$\sf \implies 2 \times 22 \times\: 2 \times34$

$\sf \implies 2992 \: m^{2}$

$\boxed{\pink{ \sf Hence, t otal \: surface \: area \: of \: cylinder = 2992 \: m^{2}}}$

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$\sf (iii). \: Volume \: of \: cylindrical \: tank = \pi (r)^{2} h$

$\sf \implies \dfrac{22}{7} \times\: 14 ^{2} \times 20$

$\sf \implies \dfrac{22}{7} \times\: 14 \times 14 \times 20$

$\sf \implies \dfrac{22}{7} \times\: 3920$

$\sf \implies 22 \times 560$

$\sf \implies 12320 \: m^{3}$

$\boxed{\pink{ \sf Hence, volume \: of \: cylindrical \: tank = 12320 \: m^{3}}}$

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$\bf \underline{Abbreviations} :$ ↴

$\sf \implies l=Length$

$\sf \implies h=Height$

$\sf \implies \pi=\dfrac{22}{7}$

$\sf \implies r=Radius$