Question

The radius of a hemispherical balloon increases from 5 cm to 10 cm as air is being pumped into it. The ratio of the surface areas of the balloon in the two cases is
plss explain your answer​

Answer 1

Step-by-step explanation:

The radius of a hemispherical balloon increases from 5 cm to 10 cm as air is being pumped.

The initial surface area of balloon = 2πr^2. sq.unit = 2π(5)^2 sq. cm

The increased surface area of balloon = 2πr^2 sq. unit = 2π(10)^2 sq. cm

$the \: ratio \: of \: surface \: area \: of \: balloon \: \: = \frac{2\pi \times 5 \times 5}{2\pi \times 10 \times 10}$

$= \frac{1}{4}$

= 1 : 4

Answer :- The ratio of a surface area of a balloon is 1 : 4.