the radius of a munoic h atom is 2.5 * 10^ -13 m what is the total atomic volume in m^3 of a mole of h atoms
Answers
Answered by
2
radius = 2.5 * 10^-13 m
Volume = 4/3 πr^3
No. Of atoms in 1 mole = 6.022*10^23
Volume = 6.022*10^23*4/3*22*7*(2.5*10^-13)^3
= 3.94*10^-14 m^3
Volume = 4/3 πr^3
No. Of atoms in 1 mole = 6.022*10^23
Volume = 6.022*10^23*4/3*22*7*(2.5*10^-13)^3
= 3.94*10^-14 m^3
Similar questions