The radius of a nucleus is 1.2 x 10-15 m. Express it in :
(a) fermi (f)
(b) Angstrom (Å)
(c) nanometre (nm)
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It has given that the radius of a nucleus is 1.2 × 10^-15 m.
(a) Fermi (f)
(b) Angstrom ( Å )
(c) nanometre (nm)
(a) Fermi is a unit of length in nuclear physics equivalent to the femtometre. i.e., 10^-15 m = 1 f
therefore radius of the nucleus = 1.2 × 10^-15 = 1.2 f
(b) Angstrom is a unit of length equivalent to the 10^-10 m. i.e., 10^-10 m = Å
now radius of nucleus = 1.2 × 10^-15 m = 1.2 × 10^-5 × 10^-10 m
= 1.2 × 10^-5 Å
= 0.000012 Å
therefore radius of the nucleus = 0.000012 Å
(c) nanometre is unit of length equivalent to 10^-9 m. i.e., 10^-9 m = nm
now radius of nucleus = 1.2 × 10^-15 m = 1.2 × 10^-6 × 10^-9 m
= 1.2 × 10^-6 nm
= 0.0000012 nm
therefore radius of the nucleus is 0.0000012 nm
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Answer:
1.2f
1.2×10^-5 A
1.2×10^-6nm
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