The radius of a planet A double the radius of the planet B if mass of planet A is MA what must be the mass of b so that the value of 'g' on B is half that of its value on A
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Answer:
from the question:
rA=rB/2(1)
9B=9A/2
from the laws of physics.
9a =Gma/ra^2 (3)
9b= gmb/rb^2(4)
replacing (3) and (4) in (2):
Gmb/rb2=GM a/2 r a²
mb/Rb² = ma/2ra²
replacing (1) in (5):
mb/rb² = ma/2(rb/2)²
mb=2mA
Explanation:
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