the radius of a planet is 4 times that of earth and its mean density is twice that of earth what is the time period of the simple pendulum on that planet if it is a second pendulum on earth.
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Answer:
Time period of simple pendulum =2π
g
L
Where L= Length of wire / thread
g= gravity of planet
g=
R
2
GM
where
G= Gravitational constant
M= Mass of planet
R= Radius of planet
M
P
=2Me
R
P
=2Re
where, P
e
stands for planet earth
T
P
∝
g
P
1
∝
M
R
2
∝
M
R
⇒T
P
=
2
2
T
e
=
2
T
e
Time period on planet is
2
times
time period on earth
solution
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