Question

The radius of a planet is R and a satellite revolves around it in a circle of radius 3R. The time period of revolution of satellite is T.Acceleration due to gravity of the planet at its surface will be

Answer 1

Explanation:

Here, R2 is the radius of circle around which satellite revolves. Here, R1 is the radius of planet. Thus, the acceleration due to gravitational of the planet at its surface is 4π2T2(R23R12) 4 π 2 T 2 ( R 2 3 R 1 2 ) .