Question

the radius of a right circular cylinder is 5cm and it's height is 9 cm find csa and tsa​

Answer 1

Question :-

• The Radius of Right Circular Cylinder is 5 cm and its Height is 9 cm . Then, find the Curved Surface Area and Total Surface Area .

Answer :-

• Curved Surface Area is 282.85 cm²
• Total Surface Area is 440 cm²

$\rule {215pt}{2pt}$

Given :-

• Radius of Cylinder = 5 cm
• Height of Cylinder = 9 cm

To Find :-

• C.S.A and T.S.A = ?

Solution :-

• Here, Radius of Cylinder is given 5 cm . Height of Cylinder is 9 cm . And, we have to find the C.S.A and T.S.A .

➻ Formula Required :-

• $\sf{Curved \: Surface \: Area = 2 \pi rh}$

• $\sf{Total \: Surface \: Area = 2 \pi r \: (r + h)}$

➻ Where ,

• R denotes to the Radius
• H denotes to the Height

➻ First, we will find the C.S.A :-

$\dag \: \: \sf{ Curved \: Surface \: Area \: = \: 2 \pi rh}$

$\Longrightarrow \: \: \sf{Curved \: Surface \: Area \: = \: 2 \times \frac{22}{7} \times 5 \times 9 }$

$\Longrightarrow \: \: \sf{Curved \: Surface \: Area \: = \: \frac{1980}{7} }$

$\Longrightarrow \: \: \bf{Curved \: Surface \: Area \: = \: 282.85 \: {cm}^{2} }$

➻ Now, let's find the T.S.A :-

$\dag \: \: \sf{ Total \: Surface \: Area \: = \: 2 \pi r \: (r + h)}$

$\Longrightarrow \: \: \sf{Total \: Surface \: Area \: = \: 2 \times \frac{22}{7} \times 5 \times (5 + 9) }$

$\Longrightarrow \: \: \sf{Total \: Surface \: Area \: = \: \frac{44}{7} \times 5 \times (14)}$

$\Longrightarrow \: \: \sf{Total \: Surface \: Area \: = \: \frac{44}{7} \times 70 }$

$\Longrightarrow \: \: \sf{Total \: Surface \: Area \: = \: 44 \times 10}$

$\Longrightarrow \: \: \bf{Total \: Surface \: Area \: = \: 440 \: {cm}^{2} }$

Hence :-

• Curved Surface Area = 282.85 cm²
• Total Surface Area = 440 cm²

$\rule {215pt}{4pt}$

Formula Used :-

$\bigstar \: \boxed {\bf{\pink{C.S.A} = 2 \times \pi \times R \times H}}$

$\bigstar \: \boxed {\bf{\pink{T.S.A} = 2 \times \pi \times R \times (R + H)}}$