Question

the radius of a right circular cylinder is doubled keeping its height same.find the ratio between volumes of new cylinder and the original cylinder

Answer 1

Let the ratio be x
Height be 1

$volume = \pi {r}^{2} h$

$\frac{22}{7} \times x \times 1 \\ \frac{22x}{7}$

New radius=2x
$volume = \pi {r}^{2} h \\ \frac{22}{7} \times 2x \times 1 \\ \frac{44x}{7}$
Ratio of new cylinder to original cylinder
$\frac{ \frac{22x}{7} }{ \frac{44x}{7} } \\ \frac{22x \times 7}{44x \times 7} \\ \frac{1}{2}$
Ratio=1:2

Answer 2

Answer:

answer is 4:1

Step-by-step explanation:

hope it helps you

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