the radius of a right circular cylinder is halved keeping the height same find the ratio of the volume reduced cylinder to that of original cylinder
Answers
Let, the radius of the previous cylinder be, 'r'
The radius of the new cylinder = r/2
Volume of the original cylinder = (22/7)*r*r*h
= (22r^2 h)/7
Volume of the new cylinder = (22/7)*(r/2)*(r/2)*h
= (22r^2 h)/28
So, the ratio is _
{(22r^2 h)/28} : {(22r^2 h)/7}
= {(22r^2 h)*7}/ {(22r^2h)*28}
= 7/28
= 1/4
= 1:4
(Ans): The ratio is 1:4
Answer:: The ratio is 1:4
Step-by-step explanation:
Let, the radius of the previous cylinder be, 'r'
The radius of the new cylinder = r/2
Volume of the original cylinder = (22/7)*r*r*h
= (22r^2 h)/7
Volume of the new cylinder = (22/7)*(r/2)*(r/2)*h
= (22r^2 h)/28
So, the ratio is _
{(22r^2 h)/28} : {(22r^2 h)/7}
= {(22r^2 h)*7}/ {(22r^2h)*28}
= 7/28
= 1/4
= 1:4