Math, asked by karunabiswas81, 3 days ago

the radius of a roller is 42 cm and length is 1.2 m . if it takes 500 revolution to move once over to level a playground find the area of playground​

Answers

Answered by palaksoni5274
10

Answer:

Radius of the roller (r)=

2

84

cm=42cm

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

=2×227×42×120=31680cm

2

∴ Area of the playground

=31680×500=15840000cm

2

100×100

15840000

m

2

=1584m

2

Answered by dsbisht449
8

Answer:

Mark me as brainliest

Step-by-step explanation:

we can change the digits from m to cm so,

Radius of the roller (r)=42

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

=2×227×42×120=31680cm ^2

∴ Area of the playground

=31680×500=15840000cm ^2

100×100

15840000

m^2

=1584m ^2

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