Question

The radius of a roller is 49 cm and its length is 125 cm. How much area of a playground will
be levelled in 400 revolutions moving once over the ground?
ANSWER IS-1540m2 But how?​

Answer 1

Step-by-step explanation:

csa of roller=2πrh

then whichever is the ans multiplyed by 700

=then csa of roller * 700

=1540 m sq

Answer 2

GIVEN THAT : - length of roller is 125 cm which means that height of the cylinder

radius of the roller = 49 cm

area covered by 1 revolution = CSA OF THE CYLINDER

CSA OF CYLINDER = 2πrh

= 2 × 22/7 × 49 × 125

= 2 × 22 × 7 × 125

= 38500 cm^2

area covered by 1 revolution 38500 cm^2

area covered by 400 revolution = 400 × 38500

=15400000cm^2

I hope it will help u.....