The radius of a roller is 49 cmn and its length is 125 cm. How much area of a playground will
be levelled in 400 revolutions moving once over the ground?
Answers
Answered by
5
GIVEN THAT : - length of roller is 125 cm which means that height of the cylinder
radius of the roller = 49 cm
area covered by 1 revolution = CSA OF THE CYLINDER
CSA OF CYLINDER = 2πrh
= 2 × 22/7 × 49 × 125
= 2 × 22 × 7 × 125
= 38500 cm^2
area covered by 1 revolution 38500 cm^2
area covered by 400 revolution = 400 × 38500
=15400000cm^2
I hope it will help u.....
Answered by
49
refer to attachment!!...❗
hope!!...it helps uhh...❣️
Attachments:
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
Math,
5 months ago
Math,
9 months ago
Science,
9 months ago
Social Sciences,
11 months ago
Math,
11 months ago